Programming can sometimes be very hard to learn especially if you have no experience in this field. Learn how to use Python and text editor VS Code the right way Hands on projects like guess the number and Snake,Water,Gun gameĬreate your own basic programs with python Hands on programming examples of operator, string, number, tuple, dictionary, set, list, random module Learn how to program in python, python functions, all basic concepts in python.Ĭoncepts of modules, conditional statements, functions,file handling The Python Second While loop makes sure that the specified number is greater than 0.Duration: 2h 3m | Video. While Loop makes certain the specified number is greater than 0, statements within the while loop divide the numbers and count the number of individual digits within the set number. If they’re equivalent, then we affirm it is an Armstrong number. Using the ‘if-else’ condition, we compare the sum with the original number. The cubes of these digits are assessed by utilizing the ‘exponent(*)’ operator. When that number is divided by 10, then the rest is the last digit of this number. We initialize sum = 0 and receive each digit number using the ‘%(modulo)’ operator. We take input from the consumer and check that the entered number is the Armstrong number. #program to check whether the given number is Armstrong or not using a while loop # take input from the user #Python program to check whether the given number is Armstrong or not num = int(input('Enter the number : ')) If they’re the same, this number is an Armstrong number. Ultimately, we check whether the sum precisely likes as the first number.Then we iterate through each digit and find the sum of these digits raised to the string’s power of length.We convert the number to a string and find its length.We accept input from consumers and convert them to Some numbers.Print(' is NOT an Armstrong number'.format(num))įollowing are the steps in the above program You can check whether a given number is Armstrong number or not in Python in number of ways: num = int(input('Please enter a number: '))ĭigits_sum += int(d) ** len_num # power operation Step 5 → result = result + pow(remainder,n)īelow is the procedure for Armstrong number in C temp = num Step 2 → Find the total number of digits in the number. Example: 407Īlgorithm to check given number is Armstrong number or not START Step 1 → Initialize result = 0 and temp = number. Let’s example it using mathematical computation.

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